$$
\gdef\Res #1{\underset{#1}{\mathrm{Res}}}
\gdef\hi{\hat {\pi }}
\gdef\ti{\tilde {\pi }}
$$
$$\begin {aligned}
\lim _{r\to 0+}\left (\frac {\ln r}2+\int _{0}^{1-r}\frac {dx}{(1-x)(1+x^{2})}\right )
&=\lim _{r\to 0+}\int _{0}^{1-r}\left (-\frac {1}{2(1-x)}+\frac {1}{(1-x)(1+x^{2})}\right )dx\\
&=\frac {1}2\int _{0}^{1}\frac {1}{1-x}\left (-1+\frac {2}{1+x^{2}}\right )dx\\
&=\frac {1}2\int _{0}^{1}\frac {1-x^{2}}{(1-x)(1+x^2)}dx\\
&=\frac {1}2\int _{0}^{1}\frac {1+x}{1+x^{2}}dx\\
&=\frac {1}2\left [\arctan x+\frac {1}2\ln (1+x^{2})\right ]_0^1\\
&=\frac {1}2\left (\frac {\pi }4+\frac {\ln 2}2\right )\\
&=\textcolor {blue}{\frac {\pi }8+\frac {\ln 2}4}.
\end {aligned}$$