$$
\gdef\Res #1{\underset{#1}{\mathrm{Res}}}
\gdef\hi{\hat {\pi }}
\gdef\ti{\tilde {\pi }}
$$
$$\begin {aligned}
\int _{0}^{1}\frac {\ln ^{2}x}{(1-x)(1+x^{2})}dx
&=\frac {1}2\int _{0}^{1}\left (\frac {1}{1-x}+\frac {1+x}{1+x^{2}}\right )\ln ^{2}xdx\\
&=\zeta (3)+\Re \int _{0}^{1}\frac {(1-i)\ln ^{2}x}{x-i}dx\\
&=\zeta (3)-\Re \left \{(1-i)\operatorname{Li} _{3}(-i) \right \}\\
&=\zeta (3)-\Re \left \{ (1-i)\left (-\frac {3}{32}\zeta (3)-\frac {\pi ^{3}}{32}i\right )\right \} \\
&=\zeta (3)+\frac {3}{32}\zeta (3)+\frac {\pi ^{3}}{32}\\
&=\textcolor {blue}{\frac {35}{32}\zeta (3)+\frac {\pi ^{3}}{32}}.
\end {aligned}$$